Ukrainian president to address food security summit in New York
Ukrinform
On Tuesday, September 20, Ukrainian President Volodymyr Zelensky will take part in a food security summit that will be held as part of the high-level week of the 77th session of the UN General Assembly.
According to Ukrinform's correspondent in New York, the event was organized on the initiative of the United States and the African Union.
The event will last from 21:00 to 23:00 Kyiv time. Zelensky is expected to deliver his speech via video link.
Ukrainian Prime Minister Denys Shmyhal will also take part in the summit. He will also hold several bilateral meetings with the heads of governments of partner countries and international financial organizations.
